Given p(x) = 0.6, p(y) = 0.3, and p(y|x) = 0.05, what are p(x and y) and p(x or y)?

p(x and y) = 0.03, p(x or y) = 0.87
p(x and y) = 0.03, p(x or y) = 0.35
p(x and y) = 0.9, p(x or y) = 0.87
p(x and y) = 0.9, p(x or y) = 0.35
p(x and y) = 0.87, p(x or y) = 0.03

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

its totaly b

your welcome btw