|4r + 8| ≥ 32
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r ≥ 6

Step-by-step explanation:

4r≥24

r≥6

See bottom for more detail on two answers

a) 6 ≤ r ≤ -10

b) (-∞,-10] ∪ [6,∞)

Step-by-step explanation:

Question:  |4r + 8| ≥ 32

Question Pt.1) 4r+8 ≥ 32     <-- All steps to Pt.1 are underlined

Question Pt.2) 4r+8 ≤ -32

1) Subtract 8 from both sides:

4r≥24

2) Divide both sides by 4:

r≥6

1) Subtract 8 from both sides:

4r≤-40

2) Divide both sides by 4:

r≤-10

This answer can be written in several ways, which include the following:

a) 6 ≤ r ≤ -10

b) (-∞,-10] ∪ [6,∞)

Footnotes:

- Answer form A is written in inequality notation

- Answer form B is written in interval notation

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

step-by-step explanation: