The hypotenuse of a right triangle is 1m longer than twice one of the other two sides. the third side of the triangle is 15m. find the lengths of the unknown side and the hypotenuse.

(this is within the unit of quadratic equations, so im not entirely sure how this would work)

Let the length of unknown side be x

So, hypotenuse = 2x + 1

By pythagorean theorem ie , a² = b² + c²

(2x + 1)² = x² + 15²

4x² + 1 + 4x = x² + 225

3x² + 4x -224

(3x +28)(x-8)

x = -9.33 , 8

Since, length can't be negative

x = 8

∴Unknown side length = 8 m

Length of hypotenuse = 2 x 8 + 1 = 17 m

Hope it helps now.

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5