On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since the church is only 12.0 miles away. on the way, however, you have to make an unanticipated stop for construction work on the road. as a result, your average speed for the first 17 minutes is only 5.0 mi/h. what average speed do you need for the rest of the trip to get you to the church on time?

Average speed   is 37.35 mi/h

Step-by-step explanation:

given data

leave =  34 minutes before

church distance =  12.0 miles

average speed first 17 minutes =  5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 ×

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed  =

Average speed  =

Average speed   is 37.35 mi/h

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98