Suppose that a bag of scrabble tiles contains 5 es, 4 as, 3 ns, and 2 bs. it is my turn and 1 draw 4 tiles from the bag. assume that my draw is uniformly random. let c be the event that i got two es, one a and one n. a. compute p(c) by imagining that the tiles are drawn one by one as an ordered sample. b. compute p(c) by imagining that the tiles are drawn all at once as an unordered sample. we have an one with m green balls and n yellow balls. two balls are drawn at random. what is the probability that the two balls have the same color? a. assume that the balls are sampled without replacement. b. assume that the balls are sampled with replacement. c. when is the answer to part (a) larger than the answer to pair (b)? justify your answer. can you given an intuitive explanation for what the calculation tells you?

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

is there supposed to be a diagram or a graph for this one? ?

step-by-step explanation:

the argument of alfred t. mahan, henry cabot lodge, and albert j. beveridge was the economically and mass production the the americans could not consume themselves. this led expansion to sell to other foreign nations for profits.

step-by-step explanation:

this is my explanation

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.