1kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). suppose the function f determines marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017. the function g determines marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017. suppose f ( 29 ) = 194 . what is the value of g ( 29 ) ? g ( 29 ) = write a formula for g using the function f .

1. g(29)=88.18

2.

Step-by-step explanation:

It is given that 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb).

1 kg = 2.2 lb

Let as consider f determines Marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017.

The function g determines Marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017.

It is given that f ( 29 ) = 194, it means the 29 Marcus's weight (in lbs) is 194.

Using the above conversion we get

Multiply both sides by 194.

It means the 29 Marcus's weight (in kg) is about 88.18.

Since 1 kg = 2.2 lb, it means weight in kg must be multiplied by 2.2 to convert it into lbs.

Divide both sides by 2.2.

Therefore the formula for g using the function f is .

thats not a system of equations, that is a solution

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110