1kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). suppose the function f determines marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017. the function g determines marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017. suppose f ( 29 ) = 194 . what is the value of g ( 29 ) ? g ( 29 ) = write a formula for g using the function f .

1. g(29)=88.18

2.

Step-by-step explanation:

It is given that 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb).

1 kg = 2.2 lb

Let as consider f determines Marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017.

The function g determines Marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017.

It is given that f ( 29 ) = 194, it means the 29 Marcus's weight (in lbs) is 194.

Using the above conversion we get

Multiply both sides by 194.

It means the 29 Marcus's weight (in kg) is about 88.18.

Since 1 kg = 2.2 lb, it means weight in kg must be multiplied by 2.2 to convert it into lbs.

Divide both sides by 2.2.

Therefore the formula for g using the function f is .

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

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