Two consecutive integers have a sum of 67. what are the two integers?

➷  We can call the first integer 'x'

Thus, the second integer would be 'x + 1'

From this, we can form an equation:

x + x + 1 = 67

Simplify this:

2x + 1 = 67

- 1 from both sides:

2x = 66

Divide both sides by 2:

x = 33

Therefore, x + 1 = 34

The 2 integers are 33 and 34.

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step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15