For problems 1-19, find the general solution of the given dif- ferential equation. when initial conditions are given, find the solution that satisfies the stated conditions. 1. y" = 0 6. y" - y' – 2y = 0 2. y" - y'=0 7. y" + 2y' + y = 0 3. y" – 9y = 0 8. 4y" – 4y' + y = 0 4. 4y" - y = 0 9. 2y" – 3y' + y = 0 5. y" – 3y' + 2y = 0 10. y" – 6y' + 9y = 0 11. y" – 8y' + 16y = 0 12. y" – 25y = 0, y(0) = 0 y'(0) = 0 13. y" + y' – 2y = 0 y(0) = 1 y'(0) = 0 14. y" + 2y' + y = 0 y(0) = 0 y'(0) = 1

is there any photos or whatever?

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.

it will take 9 minutes