Find the equation of the line with the slope - 2/9
and the y-intercept (0,2).
the equation of the line

ANSWER:  

The line equation with the slope and the y-intercept (0,2) is 2x + 9y – 18 = 0.

SOLUTION:

Given, slope of the line is and point on the line (0, 2).

We have to find the line equation.

As we have slope and a point, let us find the point slope form of the given equation.

Point slope form →

Where m is slope and is a point on that line

Here, in our problem,

Now, we get

9(y – 2) = -2x

9y – 18 = -2x

2x + 9y – 18 = 0

Hence, the line equation is 2x + 9y – 18 = 0.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

i believe the answer is c.