Solve the system algebraically check your work 2x+y- 10=0; x-y-5=0

x = 5 and y = 0 is correct solution of 2x + y -10 = 0 and x – y – 5 =0

Solution:

Two given equations which needs to be solve are  

2x + y – 10 = 0    ------ (1)

x– y – 5 = 0       ------ (2)  

Let’s modify equation (1)

2x + y – 10 = 0    

y =10 - 2x        ------ (3)

On substituting value of y from equation (3) in equation (2) we get

x – (10 – 2x) -5 = 0

x – 10 + 2x – 5 = 0

3x -15 = 0

x = 5

Substituting x = 5 in equation (3) to get value of y.

y = 10 – 2 5 = 10 – 10 = 0

So on solving given equation we get x = 5 and y = 0.

Lets substitute value of x = 5 and y = 0 in equation (1) and equation (2) to check whether these calculated values satisfies given equations or not.

For equation (1), 2 5 + 0 – 10 = 10 – 10 = 0

For equation (2), 5 – 0 – 5 = 0  

On solving, in both cases LHS = RHS for calculated values of x = 5 and y = 0.

Hence x = 5 and y = 0 is correct solution of two given equation.

angle addition postulate

2x=56

step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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