Solve each given equation and show your work tell whether each equation has one solution infinite number of solutions or no solutions.
(a) 2x+4(x-1)=2+4x
(b) 25-x=15-(3x+10)
(c) 4x=2x+2x+5(x-x)

  (a)  x = 3, one solution

  (b)  x = -10, one solution

  (c)  infinite solutions

Step-by-step explanation:

In each case, we can subtract the right side from both sides and simplify.

(a)

  (2x +4(x -1)) -(2 +4x) = 0

  2x +4x -4 -2 -4x = 0 . . . . . . eliminate parentheses

  2x -6 = 0 . . . . . . . . . . . . . . . collect terms

  x - 3 = 0 . . . . . . . . . . . . . . . . divide by 2

  x = 3 . . . . . . . . . . . . . . . . . . . add 3, one solution

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(b)

  25 -x -(15 -(3x +10)) = 0

  25 -x -15 +3x +10 = 0 . . . . . . eliminate parentheses

  2x +20 = 0 . . . . . . . . . . . . . . .collect terms

  x +10 = 0 . . . . . . . . . . . . . . . . divide by 2

  x = -10 . . . . . . . . . . . . . . . . . . add -10, one solution

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(c)

  4x - (2x+2x+5(x-x)) = 0

  4x -2x -2x +0 = 0

  0 = 0 . . . . . . . . . . . . . . . . . . . true for all values of x, infinite solutions

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve