Which problem can best be solved with the inequality 40 – 3x ≥ 5?

The problem "You bring $40 to the carnival. You need to keep at least $5 for the bus ride home. How many $3 rides can you go on?" can be solved using the given inequality.

Solution:

The given inequality is

For the best solution of the inequality, we need to subtract 40 from both the side of the equation for getting the value of x.  

Now subtracting 40 from both side we get,

Now if we put the value of x in the equation, we get,  

The value of

The answer for the problem will be maximum of 11 rides can be taken.

goog may have it for you

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3