Acollege administration has conducted a study of 190randomly selected students to determine the relationship between satisfaction with academic advisement and academic success. they obtained the following information: of the 68students on academic probation, 34are not satisfied with advisement; however, only 25of the students not on academic probation are dissatisfied with advisement. what is the probability that a student selected at random is onacademic probation and is not satisfiedwith advisement?

The probability that a student selected at random is on academic probation and is not satisfied with advisement is 0.1789

Step-by-step explanation:

Consider the provided information.

Out of 68 students on academic probation, 34 are not satisfied with advisement; That means 68-34=34 are satisfied with advisement.

If 68 students are in academic then the non academic students probation will be: 190-68=122

Only 25of the students not on academic probation are dissatisfied with advisement.

That means 122-25=97 students are satisfied.

According to the provided information draw the table as shown.

                                               Satisfied   Not satisfied   Total

Academic probation                  34              34                68

Non academic probation          97              25               122

Total                                            131              59               190

Now we need to determine the probability that a student selected at random is on academic probation and is not satisfied with advisement.

On academic probation and is not satisfied with advisement = 34

The total number of cases is 200.

Substitute the respective values:

Hence, the probability that a student selected at random is on academic probation and is not satisfied with advisement is 0.1789

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step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.