Find the first five terms of the sequence in which a1 = 6 and an = –3an – 1 – 12, if n ≥ 2.

a. 30, 78, –246, 726, –2190

b. 6, –30, 78, –246, 726

c. 6, 6, –30, 78, –246

d. –15, –18, –21, –24, –27

Step-by-step explanation:

so whats the answer?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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