Ateam of cancer research specialists received a grant of $500,000 to be used for cancer research. they deposited some of the money in a 10% simple interest account and the remainder in an 9% annual simple interest account. how much was deposited in each account if the annual interest is $49,500?

Step-by-step explanation:

Let x represent the amount invested at 10%. Then the total interest earned per year is ...

  0.10x + 0.09(500,000-x) = 49,500

  0.01x = 49500 -45000

  x = 4500/0.01 = 450,000

$450,000 was deposited in the 10% account; $50,000 was deposited in the 9% account.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18