How many solution does the equation have? -10(x-1)=10-10x

ANSWER:  

The equation -10(x – 1) = 10 - 10x have infinitely many solutions.

SOLUTION:

Given, equation is -10(x – 1) = 10 - 10x.

We need to find how many solutions are there for above equation.

Now,  

-10( x – 1 ) = 10 - 10x

-10x – ( -10 ) × 1 = 10 – 10x

-10x + 10 × 1 = 10 – 10x

-10x + 10 = 10 – 10x

10 – 10x – 10 + 10x = 0

(10 – 10) + (-10x + 10x) = 0

(0) + (0) = 0

0 = 0

L.H.S = R.H.S

So, for any value of x the equations becomes true.

Hence, the equation have infinitely many solutions.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: