Fanny had 5 times as many toys as simon. after their aunt gave each of them 108 toys, fanny had twice as many toys as simon. how many toys do they have in all now?

ANSWER:

The toys with Fanny and Simon is 432.

SOLUTION:

Let, the number of toys with fanny be x and number of toys with Simon be y.

Given that, Fanny had 5 times as many toys as Simon.

Then, x = 5y ---- (1)

And after their aunt gave each of them 108 toys, Fanny had twice as many toys as Simon.  

x + 108 = 2(y + 108)

x + 108 = 2y + 216

x – 2y = 216 – 108

x – 2y = 108 ---- (2)

Now substitute the (1) in (2)

5y – 2y = 108

3y = 108

y = 36

Again substitute y value in (1)

x =

x = 180

Now, total toys with them = (x + 108) + (y + 108)

= (180 + 108) + (36 + 108)  = 432

Hence, the toys with fanny and simon is 432.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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