Which one of these strategies would eliminate a variable in the system of equations 8x+5y=-7, -7x+6y=-4

For this case we have the following system of equations:

If we want to solve the system by the "elimination" method, we must multiply some (or two) of the equations by a number such that when one is added, one of the variables is eliminated.

Multiplying by 6 the first equation we have:

Multiplying by -5 second equation we have:

If we add both equations, the variable y is eliminated.

We can also multiply the first equation by 7:

We multiply the second equation by 8:

Adding the equations eliminates the variable x.

One strategy may be to multiply the first equation by 7, the second equation by 8 and add.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3