Need

a stadium has 49,000 seats. seats sell for $30 in section a, $24 in section b, and $18 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,246,800 from each sold-out event. how many seats does each section hold?

Step-by-step explanation:

Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.

The revenue from those seats is, ...

  24,500×$30 = $735,000

so the revenue from B and C seats is ...

  $1,246,800 -735,000 = $511,800

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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...

  24b +18(24500-b) = 511800

  6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms

  b = 70,800/6 = 11,800 . . . . . . . seats in B section

  24,500 -11,800 = 12,700 . . . . . seats in C section

There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.