Neep

a stadium has 55,000 seats. seats sell for $35 in section a, $20 in section b, and $15 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,448,500 from each sold-out event. how many seats does each section hold?

section a holds seats.
section b holds seats.
section c holds seats.

Step-by-step explanation:

Section A holds half the seats in the stadium, so 27,500 seats.

Revenue from a sold-out section A will be ...

  $35×$27500 = $962,500

so the combined revenue from B and C seats is ...

  $1,448,500 -962,500 = $486,000

If we let "b" represent the number of section B seats, then the number of section C seats is (27,500 -b) and the revenue from sold-out sections B and C will be ...

  20b +15(27500 -b) = 486000

  5b = 73,500 . . . . . . . . subtract 412,500

  b = 14,700 . . . . . . . . . . divide by 5; number of Section B seats

  27,500-b = 12,800 . . . number of Section C seats

There are 27,500 Section A seats, 14,700 Section B seats, and 12,800 Section C seats.

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

only 10/60 isn't equivalent

hope this : )