Write an equation of a line which is passing through the point (8, −6) and is parallel to another line, whose slope is −2

ANSWER:  

The equation of the line passing through the point (8,-6) and parallel to line with slope -2 is 2x + y -10 = 0.

SOLUTION:

Given, a line is passing through the point (8, −6) and is parallel to another line, whose slope is −2

We need to find the equation of the line.

We know that, parallel lines will have same slope.

So slope of the required line is -2.

Now, we have a point on the line and slope of the line, so we can use point – slope form to find the line equation.

Point slope form is given as

Where "m" is the slope and is a point on that line.

Here,

Now, substitute values in point slope form.

y – (-6) = -2(x – 8)

y + 6 = -2x - 2(-8)

y + 6 = -2x + 16

2x + y +6 -16 = 0

2x + y -10 = 0

Hence, the equation of the line is 2x + y -10 = 0.

could you give more information?

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2