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Mathematics, 12.10.2019 21:20 sankarjgoutham

An object is launched straight up into
the air at an initial velocity of 32 feet
per second. it is launched from a height
of 3 feet off the ground. its height h, in
feet, at t seconds is given by the
equation h = -8t^2 + 32t + 3. find all
times t that the object is at a height of
27 feet off the ground.

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Answers: 3

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An object is launched straight up into
the air at an initial velocity of 32 feet
per secon...

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