Proving the parallelogram side theorem
given: abcd is a parallelogram,
prove: ab cd and bc da
angles
segments
triangles su
nes
zbac
2bca
dac
zdca
statements
reasons
assemble the proof by dragging tiles to
the statements and reasons colus.

answer: l

step-by-step explanation:

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0