He longer base of isosceles trapezoid is 12 cm. the side is 5 cm. the acute angle is 37º. find the shorter base.

The shorter base is 4.0136.

Given that,

Based on the above information, the calculation is as follows:

x = 5 cos 37

x = 3.9932 cm

Now  

The shorter base = longer base - 2(3.9932)

= 12 - 7.9864

= 4.0136

Therefore we can conclude that the shorter base is 4.0136.

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4.01 cm to the nearest hundredth.

Step-by-step explanation:

Consider the triangle formed by the perpendicular line drawn from one endpoint of the shorter base to the longer base.

cos 37 = x / 5

x = 5 cos 37

x = 3.9932 cm

The shorter base = longer base - 2(3.9932)

= 12 - 7.9864

= 4.0136

idk sry

step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: