State how many imaginary and real zeros the function has.

f(x) = x3 + 5x2 + x + 5

Step-by-step explanation:

f(x) = x³ + 5x² + x + 5

f(x) = x² (x + 5) + x + 5

f(x) = (x² + 1) (x + 5)

The function has one real root (x = -5) and two imaginary roots (x = ±i).

(-1,-0.5)

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)