An airline has a policy of booking as many as 23 persons on an airplane that can seat only 22. (past studies have revealed that only 85.0% of the booked passengers actually arrive for the flight.) find the probability that if the airline books 23 persons, not enough seats will be available. is it unlikely for such an overbooking to occur?

The probability that the airline books 23 people is 0.024. We can consider that overbooking is something unlikely to occur.

Step-by-step explanation:

This is binomial experiment so we can use the probability fuction of a binomial distribution:

P(x)=·pˣ·(1-p)ⁿ⁻ˣ

whrere:

p: is the probability of a passenger arrive for the flight (0.85)

n: number of experiments

Hence;

P(x=23)=·(0.85)²³·(1-0.85)²³⁻²³

P(x=23)=(0.85)²³=0.024

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)