Is the sum of the areas of two smaller
squares equal to the area of a large square
if the side lengths of the squares are 8 feet,
5 feet, and 3 feet? note that the area of
a square is s2, where s is the side length.
explain.

Colin listed his assets and liabilities on a personal balance sheet. colin’s balance sheet (august 2013) assets liabilities cash $1,500 credit card $500 stocks $800 rent $800 car $5,000 car loan $1,200 coin collection $1,200 student loan $5,000 total total which statement is true about the total assets and the total liabilities? the total of the assets and the liabilities are the same. the total of the assets is greater than the total of the liabilities. the total of the assets is less than the total of the liabilities. the total of the assets cannot be compared to the total of the liabilities.

To solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second equation. what was the resulting equation? 3y=12x x^2/4+y^2/9=1

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.