Four students provide the following approximations for 0.89.
anyah states that _0.89 is between 0.44 and 0.45 because 0.44< < 0.45.
matthew states that v0.89 is between 0 and 1 because i < 0.89 < 1.
rhoda states that 0.89 is between 0.9 and 1.0 because 0.92 0.89 < 1.02.
ming states that v0.89 is between 0.93 and 0.95 because (0.93)2 < 0.89 < (0.95)2.

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.