The sum of two numbers is 66. two times the smaller number is 15 more then th larger number what are the numbers

Let x = big number

Let y = small number

x + y = 66...Equation A

2y = x + 15...Equation B

We have two equations in two unknowns.

x + x + 15 = 66

2x = 66 - 15

2x = 54

x = 54/2

x = 27

Plug x = 27 into EITHER equation above to find y.

I will use Equation A.

x + y = 66

27 + y = 66

y = 66 - 27

y = 39

The two numbers are 27 and 39.

Numbers are 27 , 39.

Step-by-step explanation:

Given : The sum of two numbers is 66. two times the smaller number is 15 more then the larger number .

To find : what are the numbers.

Solution : We have given sum of two numbers is 66

Let the smaller number = x

Larger number = y.

According to question :

two times the smaller number is 15 more then the larger number .

Two times the smaller number =2x

15 more than the larger number y + 15.

2x = y + 15.

Now subtract 15 form both sides

y = 2x - 15.

Second condition :

Sum of two number is  66.

x + y =66

Now plug the y =2x -15.

x + 2x -15 = 66

3x -15 = 66.

On adding both sides by 15

3x = 66 + 15.

3x = 81

On dividing both sides by 3

x = 27.

Then , 27 + y = 66.

On subtracting both sides by 27.

y = 39.

Therefore, Numbers are 27 , 39.

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

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x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

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x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

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x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!