Aprojectile is fired from a cliff 210 feet above the water at an inclination of 45 degree to the horizontal, with a muzzle velocity of 45 feet per second. the height h of the projectile above the water is given by h(x) = -32x^2/(45)^2 + x +210 where x is the horizontal distance of the projectile from the face of the cliff. use this information to answer the following.
at what horizontal distance from the face of the cliff is the height of the projectile a maximum? x = feet

31.64 feet

Step-by-step explanation:

The height is given by the equation:

where x is the horizontal distance of the projectile from the face of the cliff.

If the height is maximum, then its derivative must be h'(x)=0. Remembering that the derivative of is , we have:

And we want h'(x)=0, so:

This will give us the horizontal distance from the face of the cliff when the height of the projectile is at its maximum. We then do:

muyb ajo

step-by-step explanation:

jegosu

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.