Acatalog company that receives the majority of its orders by telephone conducted a study to determine how long customers were willing to wait on hold before ordering a product. the length of waiting time was found to be a variable best approximated by an exponential distribution with a mean length of waiting time equal to 2.8 minutes (i. e. the mean number of calls answered in a minute is 1/2.8). what proportion of callers is put on hold longer than 2.8 minutes?

0.3679

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

, where  is the mean of the distribution.

Given :  A mean length of waiting time equal minutes

i.e. Mean number of calls answered in a minute

Now, the proportion of callers is put on hold longer than 2.8 minutes is given by :_

Hence, the proportion of callers is put on hold longer than 2.8 minutes = 0.3679

could you reply to this with the question so i can ?

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer