Amathematics textbook has 100 pages on which typographical errors in the equations could occur. suppose there are in fact two pages with errors. what is the probability that a random sample of 20 pages will contain at least one error?

0.0396

Step-by-step explanation:

the probability of one page having an error is p= 2/100 = 1/50

if the letter q is the probability of not having an error then q = 49/50

Using binomial probability:

n is the sample size--> n = 20

And we want the probability that a random sample of 20 pages will contain at least one error, this is the same as 1 minus the probability of none of the 20 pages containing an error:

probability(x ≥ 1) = 1 - probability( x = 0)

Using the binomial probability equation

Probability( x=0 ) =

Probability( x=0 ) = = 0.9604

Thus,

probability(x ≥ 1) = 1 - 0.9604= 0.0396

step-by-step explanation: noo

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!