To qualify for a police academy, applicants are given a test of physical fitness. the scores are normally distributed with a mean of 64 and a standard deviation of 9. if only the top 20% of all applicants are selected, find the cut off score. round up your answer to the nearest integer.

X₀ = 71.65

Step-by-step explanation:

given,

mean (μ ) = 64

standard deviation (σ) = 9

                                 σ²  = 81

selected candidate are top 20 % candidate

P( X > X₀)  = 0.2

P( Z > Z₀)  = 0.2

X₀ = 71.65

Hence, the cut off score is equal to X₀ = 71.65

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)