For what value of x is sin x = cos 19º, where 0°< x < 90°

Check the picture below, that one in the picture is just an example of the correspondence of sine and cosine in a right-triangle, in this case, we're in the 0° < x < 90°, so in the I Quadrant, and thus we have a right-triangle.

to make it short, sin(90° - 19°) = cos(19°), or that is sin(71°), thus x = 71.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)