What is the distance between point (-3, 1) and point (4, 2) rounded to the nearest tenth? 8 units

50

Step-by-step explanation:

You have to apply the distance formula:

(x,y)

(-3,1)

(4,2)

√(x2-x1)²+(y2-y1)² = √(4+3)²+(2-1)² = √7²+1² = √49 + 1 = 50

The distance between the point (-3,1) and (4,2) is 7.1  units

Solution:

The distance between two points is given as

  ---- eqn 1

Where are the coordinates of the given points

From question, given that the points are (-3, 1) and (4, 2)

Hence we get      

By using eqn 1, we get the distance between the two points as,

Rounding to the nearest tenth, we get the answer as 7.1

Hence the distance between the point (-3,1) and (4,2) when rounded to nearest tenth is 7.1