The vertices of the pentagon abcde are a(0,4), b(4,0), c(3,- 4), d(-3,- 4), e(-4,0). if the pentagon is translated 5 units down and 4
units right, the new vertices are:

a. a'(4, -1), b'(8,-5), c'(7,-9), d'(1,-9), e'(0,-5)
b. a'(4, -1), b'(8,-5), c'(7,-9), d'(1,-9), e'(1,-5)
c. a'(4, -1), b'(5,-5), c'(7,-9), d'(1,-9), e'(0,-5)
d. a'(4, -1), b'(8,-5), c'(7.-9), d'(0,-9), e'(0,-5)

The answer to your question is: a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)

Step-by-step explanation:

pentagon ABCDE

Translated 5 units down and 4 units right

                               Changes                                    Final Vertices

A (0 , 4)                   A (0 + 4 , 4 - 5)                           A (4, -1)

B (4 , 0)                   B (4 + 4, 0 - 5)                            B (8, -5)

C (3 , - 4)                 C (3 + 4, - 4 - 5)                          C (7, -9)

D (-3 , - 4)                D (-3 + 4, - 4- 5)                         D (1, -9)

E (-4 , 0)                   E (-4 + 4, 0 - 5)                          E (0, -5)