Which ordered pair is a solution to the system of equations? use any method to solve. 2x-y=5 3x+2y=4

Hi

2x-y=5

3x+2y=4

We need to solve 2x-y=5 for y

Now let's start by adding -2x to both sides

2x-y-2x=5-2x

-y=-2x+5

Divide both sides by -1 so we eliminate the negative sign

-y/-1=-2x+5/-1

y=2x-5

Now substitute 2x-5 for y in 3x+2y=4

3x+2y=4

3x+2(2x-5)=4

3x+4x-10=4

7x-10=4

Add 10 to both sides

7x-10+10=4+10

7x=14

Divide both sides by 7 so we can find the value for x

7x/7=14/7

x=2

Now substitute 2 for x in y=2x-5 so we can find the value for y

y=2x-5

y=(2)(2)-5

y=4-5

y=-1

(2,-1)

I hope that's help:0

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.