Find three consecutive integers such that the sum of the first and twice the second is equal to the third plus four

The three consecutive integers are 2,3,4

Step-by-step explanation:

Let the three consecutive integers be represented as x,x+1,x+2

As per the given condition, the sum of the first and twice the second integer is equal to the third integer plus 4.

Representing it in the form of an equation:

x + 2*(x+1) = (x+2) + 4

=> x + 2x + 2 = x+6

=> 3x + 2 = x + 6

=> (3x -x) = 6 - 2

=> 2x = 4

=> x = 4/2 = 2

So the three integers are 2,3,4

Verification: 2 + 2*3 = 8

                    4 + 4 = 8

So the requirement is satisfied by these integers.

idk

step-by-step explanation:

i don't know

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.