How to solve 4a+8> 11a+15and 13-14a< 13-3a

Step-by-step explanation:

4a + 8 > 11a + 15

Subtracting 4a both sides

8 > 11a - 4a + 15

Subtracting 15 both sides

8-15 > 7a

-7 > 7a

Dividing both sides by 7

-7/7 > a

-1 > a

13 - 14a < 13 - 3a

Subtracting both sides by 13

13-13 -14a < -3a

Adding 14a both sides

0 > -3a + 14a

0 > 11a

Dividing 11 both sides

0 > a

Hope this helps!

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for