Mathematics, 05.10.2019 10:30 evazquez
Y=-6x²-1 find the minimum or a maximum value
Answers: 2
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ y = -6x^2-1\implies y = -6(x-\stackrel{h}{0})^2\stackrel{k}{-1}\qquad \qquad \stackrel{vertex}{(0,-1)}\qquad \qquad \stackrel{maximum}{y = -1}](/tpl/images/0289/1642/6a196.png)
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