![\bf BC=2BA\\ BE = 2BD \end{cases} \cfrac{BC}{BE}=\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BA}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BD}\implies \cfrac{BC}{BE}=\cfrac{BA}{BD}\impliedby \begin{array}{llll} \textit{equal ratio of sides}\\ \textit{similar triangles} \end{array}](/tpl/images/0288/6885/a0d5c.png)
Can someone me with this? i don’t understand what is given.
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Mathematics, 05.10.2019 07:30 em387p3s1zr
Can someone me with this? i don’t understand what is given.
Answers: 1
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