F(x)=1/2x^2

find the x and y intercepts

X and Y intercepts of a line or graph or curve means, where the line or curve or graph  cuts or intersects (or touches in extreme case) X axis or Y axis. The number of intercepting points may be one or more or there may not be any intersections(or intercepts) or touching.

If x and y are related  by an equation,y=f(x), then the x interecept is got by putting y=0  and solving for x value. And the y intercept is got by putting x=0 and  solving for y value.

Finding x intercept:

Put y=0 in y=2x^2-4x+5  and solve for x.

2x^2-4x+5=y. The same equation reversed for my convenience please.

2x^2-4x+5= 0,  as y needs to be put to 0

2(x^2-2x)+5=0, rearranged .

2[(x-1)^2 -1}+5=0, rearranged.

2(x-1)^2-2 =-5.

2(x-1)^2=-5+2 .

2(x-1)^2=-3

(x-1)^2=-3/2

x-1= + or - sqrt(-3/2)

x=1+sqrt(-3/2) or

x=1-sqrt(-3/2).

Both  x values are imaginary. So no real X intercepts.

So the given curve do not cut X axis , as the zeros of the expression, 2x^2-4x+5 are imaginary.

Finding Y intercetpt:

Put x=0

y=2*0^2-4*0+5

y=5.

The given curve cuts (or intercepts) axis at  y = 5.

Point to ponder for you:

Your answer (0,5) is the coordinates of the point, where 2x^2-4x+5 cuts Y axis. The Y cordintate alone 5 where the curve cuts the Y axis is the Y intercept. You are very very nearly correct.

Where is the equation?

f(x) = 2x^2-4x+5 is the equatuation, or

y=2x^2-4x+5 is the equation.

Here x is the variable and for  any value of x , you can find the corresponding value of 2x^2-4x+5 and that is the value of y or f(x).

Example : for x=1, 2x^2-4x+5=2*1^2-4*1+5=2-4+5=3.

So y=3, when x=1.

Hope this helps.

its a straight line parallel to the time axis

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.