What is the area of a rectangle with vertices of (-1,1), (8,-2), (6,-8),and (-3,-5)?

3600

Step-by-step explanation:

We are given the four vertices of the rectangle with the points:

A (-1,1) B(8,-2) C(6,-8) D(-3,-5)

We have to apply the distance formula to find the lenghts of the sides of the rectangle AB, BC, CD, DA √(x2-x1)²+(y2-y1)²

AB = √(8+1)²+(-2-1)² = √9² - 3² = 81 + 9 = 90

BC = √(6-8)²+(-8+2)² = √-2² - 6² = 4 + 36 = 40

CD = √(-3-6)²+(-5+8)² = √-9²+ 3² = 81 + 9 = 90

DA = √(-1+3)²+(1+5)² = √2² + 6² = 4 + 36 = 40

Now, having four sided of the rectangle, we find its area.

A = 90 * 40 = 3600

50x5=$250

step-by-step explanation:

irrational, cannot