a loan of $100,000 is made today. this loan will be repaid by 10 level repayments, followed by a final smaller repayment, i. e., there are 11 repayments in total.

the first of the level repayments will occur exactly 2 years from today, and each subsequent repayment (including the final smaller repayment) will occur exactly 1 year after the previous repayment. explicitly, the final repayment will occur exactly 12 years from today.

if the interest being charged on this loan is 3.6% per annum compounded half-yearly, and the final smaller repayment is $270,

(c) calculate the amount of the level repayments.

p = $ 12521.82

Step-by-step explanation:

Interest Rate = 3.6 %, Compounding Frequency: Semi-Annual, Equivalent Annual Interest Rate %

Number of Repayments is 11 with 10 being equal in magnitude and the last one being worth $ 270, the first repayment comes at the end of Year 2

Let  $ p  be the  level payments that required. Therefore,

100,000 - 176.01 = p x 7.972

p = $ 12521.82

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18