5. a tank initially contains 20 lb of salt dissolved in 200-gallon of water. starting at time t = 0, a solution containing 0.5 lb of salt per gallon enters the tank at a rate of 4 gallons per minute and the well-stirred solution is withdrawn at the same rate. (a) find the amount(in lb) of salt q in the solution as a function of t in minutes. (b) find the time at which the amount of salt in the tank reaches 50 lb. (c) find the quantity of salt in the solution as t + .

(a) Amount of salt as a function of time

(b) The time at which the amount of salt in the tank reaches 50 lb is 23.5 minutes.

(c) The amount of salt when t approaches to +inf is 100 lb.

Step-by-step explanation:

The rate of change of the amount of salt can be written as

Then we can rearrange and integrate

Then we have the model of A(t) like

(b) The time at which the amount of salt reaches 50 lb is

(c) When t approaches to +infinit, the term e^(-0.02t) approaches to zero, so the amount of salt in the solution approaches to 100 lb.

chicken nugget stir fry

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584