Alocal television station plans to air 188 episodes of a long-running comedy series. if the station airs 8 episodes per week, how many full weeks will pass before it must begin re-airing previously shown episodes? how many unaired episodes will be shown the following week before the previously aired episodes are rerun? the number of full weeks that pass will be weeks. (round to the nearest whole number as needed.) there will be unaired episodes shown before the previously aired episodes are rerun.

There will pass 23 full weeks and the next week it will have to show 4 unaired episodes before the previously shown ones are re-run.

Step-by-step explanation:

a) First, we know that the station airs 8 episodes per week, therefore, to know how many weeks we need to air 188 episodes we are going to divide the total amount of episodes between the number of episodes aired per week. This is 188/8 = 23.5.

Therefore there will pass 23 full weeks before it must begin re-airing previously shown episodes.

b) To know how many unaired episodes will be shown the following week before the previously aired episodes are rerun, we will see how many episodes will be transmitted after 23 weeks. We need to multiply the number of episodes per week by 23 weeks. 8 x 23 = 184.

Therefore, by week 24, there will be 4 episodes left from the 188 to air for the first time and then the other 4 will be previously aired episodes.

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.