Aspeedy rabbit is hopping to the right with a velocity of 4.0m/s when it sees a carrot in the distance. the rabbit speeds up to its maximum velocity of 13m/s with a constant acceleration 2.0m/s2 rightward.

how many seconds does it take the rabbit to speed up from 4.0m/s to 13m/s

t = 4.5 seconds

Step-by-step explanation:

initial velocity = 4.0 m/s

final velocity = 13 m/s

acceleration = 2.0 m/s2

t = (final velocity - initial velocity) / acceleration

t = (13 - 4.0) / 2.0

t = 4.5 seconds

Step-by-step explanation:

We know that:

Now, to calculate the time, we must use this equation:

This means that the rabbit needs 4.5 seconds to speed up from 4m/s to 13 m/s. In this type of problem, we just need to read carefully if there are initial () and final speed (), and acceleration, because that's the case when we use the equation showed.

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3