How do i write this equation in slope- intercept form?

y = 3/8x + 43/8

Step-by-step explanation:

first multiply 3/8 with the parentesis

y - 2 = 3/8 x + 27/8

y = 3/8x +27/8 + 2

y = 3/8x +43/8

*The equation of the line that is perpendicular should have a slope of -8/3, so the answer should be:

y - 2 = -8/3(x - -9)

y - 2 = -8/3x -24

y = -8/3x -24 + 2

y = -8/3x -22

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

3.76%

step-by-step explanation: