Mathematics, 02.10.2019 19:20 accounting73
The height h, in feet, of a ball that is released 4 feet above the ground with an initial velocity of 80 feet per second is a function of the time t, in seconds, the ball is in the air and is given by
h(t)=-16t^2+80t+4, 0 < t < 5.04
a. find the height of the ball above the ground 2 seconds after it is released.
b. find the height of the ball above the ground 4 seconds after it is released.
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Answers: 2
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