Exercise 1 below is a proof showing that two logical expressions are logically equivalent. label the steps in the proof with the law used to obtain each proposition from the previous proposition. the first line in the proof does not have a label. (p →9)(qv) (p v a) ^ (qv) (q vap) ^ ( v p) qv(pap) qv (p 4-p) qvf

n

step-by-step explanation:

0 is its x and y coordinate

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116